Election in Alabama
1832 United States presidential election in Alabama
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← 1828 | November 2 – December 5, 1832 | 1836 → |
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| | | Nominee | Andrew Jackson | | | Party | Democratic | | Home state | Tennessee | | Running mate | Martin Van Buren | | Electoral vote | 7 | | Popular vote | 14,286 | | Percentage | 99.97% | | |
President before election John Quincy Adams Democratic-Republican | Elected President Andrew Jackson Democratic | |
Elections in Alabama |
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Government |
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The 1832 United States presidential election in Alabama took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose seven representatives, or electors, to the Electoral College, who voted for president and vice president.
Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Alabama by a margin of 99.94%.
Results
See also
References
- ^ "1832 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved April 10, 2013.
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